![]() ![]() If we want to exclude the straight flushes, we need to subtract 4*2^10 from the 8^10 term since there are 2 cards of each rank in each of the 4 suits. For each rank there are 8 possible cards so this leads to 8^10 = 1,073,741,824 combinations for any given rank sequence. The math with wilds would be a lot more difficult.įor a natural 10-card straight, we have 3 rank sequences possible: 1-10, 2-11, and 3-12. Correct me if I'm wrong, but I'm assuming you got dealt a natural 10 card straight.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |